Correctness of mixed signed/unsigned arithmetic

I'm implementing signed and unsigned integers in my language. They are represented in C as signed long and unsigned long respectively.

How to deal with potentially mixed signed and unsigned arithmetic ...

Main question is how did it come to this that you have to subtract a signed integer from an unsigned one. · No easy answers here, but restricting ...

Why Not Mix Signed and Unsigned Values in C/C++?

However, if the type contains values not representable in the signed promoted type, the promoted type is instead unsigned. For example, unsigned ...

Mixed signed/unsigned remainder operation - Forums - Accellera

I know that I am mixing sizes and signed/unsigned but I am intrigued what causes the result to be 5. I was expecting either -128%9=-2 (or -128%- ...

Footguns with "signed + unsigned => signed"? - Reddit

In C, any arithmetic binary expression with an unsigned int and a signed int will promote to the unsigned int. There are a bunch of well known footguns due to ...

What are some problems caused by mixing signed and unsigned ...

In Java, the result of a mix of signed and unsigned integers will depend on the type of the variables involved. If both variables are of the ...

Signed/Unsigned operations and undefined behaviour

This function alone could raise UB if we apply to a negative value, but all the positive signed values fit in the corresponding unsigned type, ...

mixed-sign arithmetic and auto - Google Groups

int i = -3; unsigned u = 2; int x = (i + u) / 2;. The "correct" value is zero, but x receives ...

How to Write Multiplies Correctly in C Code - Texas Instruments

The rules become somewhat strange when mixing signed and unsigned types. This step is called the “arithmetic conversions.” Both of these can be confusing ...

Can someone explain the history around implicit conversion when ...

If the Standard had specified that mixed signed and unsigned comparisons must be processed in numerically-correct fashion, generating ...

Solving an ambiguity concerning unsigned and signed integers

Signed vs unsigned trapping addition/subtraction. Trapping arithmetic causes a trap/exception if the operation overflows or underflows. For ...

C++ Core Guidelines: Rules to Statements and Arithmetic - LinkedIn

If you mix signed and unsigned arithmetic, you will not get the expected result. ... The Type-Traits Library: Correctness. Rainer Grimm 2y ...

Almost Always Unsigned

The need for signed integer arithmetic is often misplaced as most integers never represent negative values within a program. The indexing of ...

unsigned vs signed - Is Bjarne Mistaken? - Google Groups

... mixed signed/unsigned arithmetic can easily lead to subtle errors, signed arithmetic should ... limit the "correct" range to INT_MAX numbers ...

Lecture 16 – Signed Integers and Arithmetic - UMBC

for a N-bit X, if the msb is 1 the value is the following difference: 2 N 2^{N} 2N - $unsigned(X); for a 16-bit value X, if the msb is 1, the value is the ...

4.5 — Unsigned integers, and why to avoid them - Learn C++

First, with signed values, it takes a little work to accidentally overflow the top or bottom of the range because those values are far from 0.

Pitfalls in C and C++: Unsigned types | Sound Software .ac.uk

An int is signed by default, meaning it can represent both positive and negative values. An unsigned is an integer that can never be negative. If you take an ...

INT02-C. Understand integer conversion rules - Confluence

As a result of the usual arithmetic conversions, the signed int is converted to unsigned, and the addition takes place between the two unsigned int values. Also ...

Should I use Signed or Unsigned Ints In C? (Part 2) - Blog

In a live Q/A, Bjarne gives his thoughts on signed and unsigned integers: "Whenever you mix signed and unsigned numbers you get trouble. The ...

The Usual Arithmetic Confusions - Shafik Yaghmour's Blog

When we mix signed and unsigned types a conversion to one of these types will be required. · When dealing with integral types smaller then int ...